Mercury has an average distance to the sun of 0.39 AU. In two or more complete sentences, explain how to calculate the orbital period of Mercury and then calculate it.
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"According to Kepler's law, the expression P2/a3 is approx equal to 4pi2/GM where
P = period,
a = average orbital distance = 0.39 AU = 58,343,169,871 metres
G = universal gravitational constant = 6.67408*10^-11 m3 kg-1 s-2
M = mass of the Sun = 1.989*1030 kilograms.
Substituting these values into the expression and solving gives
P2 = 59061382597774 seconds2 which implies that P = 7685140 seconds. This equals 88.9 Earth days.
Hence Mercury’s orbital period will take 88.9 days as per earth calculation.
"
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