Question

mercury in a faulty centigrade thermometer stands at 5 degree Celsius mark and placed in melting Ice and 95 degrees when placed in boiling water what will be the reading when it when it is placed in contact with a body at 40 degree Celsius​

Answer 1

(T-LFP)÷(UFP-LFP) = (F -32)÷180

T= given temp in scale

LFP- lower fix point/ice point of given scale

UFP- Upper fix point/steam point of given scale

F- temp in farenh. scale

(52-5)÷(99-5)=(F-32)÷180

on solving F = 112°F...

Hope it helped you...if did then follow nd rate the ans.

Hope it helps.

Answer 2

Answer:

atleast put the..value which is in your given question