Question

prove that area of trapezium is half the product of its height and the sum of parallel sides​

Answer 1

Let ABCD be a trapezium in which AB||CD

Draw CE ⊥ AB and AF ⊥ CD (Extended)

Let AB = a, CD = b and CE = AF = h

Hence area of trapezium ABCD = area of triangle ABC + area of triangle ADC

= (1/2) ah + (1/2) bh

= (1/2) h[a + b] sq units