Question

Merge the three arrays provided to you to form a one 4x4 array. [Hint: Check the function np.transpose()] Input: Array 1: 3*3 [[7, 13, 14] [18, 10, 17] [11, 12, 19]] Array 2: 1-D array [16, 6, 1] Array 3: 1*4 array [[5, 8, 4, 3]]

Answer 1

Explanation:

one. 4x4 array. [Hint: Check the function np.transpose()] Input: Array 1: 3*3 [[7, 13, 14] [18, 10, 17] [11, 12, 19]] Array 2: 1-D array [16, 6, 1] Array 3: 1*4 array [[5, 8, 4, 3]].. .....

Answer 2

Merging arrays:

Merges the elements of one or more arrays together so that the values of one are appended to the end of the previous one. It returns the resulting array.

Code:

#include<iostream>

using namespace std;

void mergeArrays(int arr1[], int arr2[], int n1,

                            int n2, int arr3[])

{

   int i = 0, j = 0, k = 0;

   while (i<n1 && j <n2)

   {

      if (arr1[i] < arr2[j])

           arr3[k++] = arr1[i++];

       else

           arr3[k++] = arr2[j++];

   }

     while (i < n1)

       arr3[k++] = arr1[i++];

   while (j < n2)

       arr3[k++] = arr2[j++];

}

int main()

{

   int arr1[] = {1, 3, 5, 7};

   int n1 = sizeof(arr1) / sizeof(arr1[0]);

 

   int arr2[] = {2, 4, 6, 8};

   int n2 = sizeof(arr2) / sizeof(arr2[0]);

 

   int arr3[n1+n2];

   mergeArrays(arr1, arr2, n1, n2, arr3);

 

   cout << "Array after merging" <<endl;

   for (int i=0; i < n1+n2; i++)

       cout << arr3[i] << " ";

 

   return 0;

}

#SPJ3