Question

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Question:- The length and breadth of a rectangular field are in the ratio 3:2 . If the area of the field is 3456 m². find the cost of fencing it at Rs 60/m².

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Answer 1

LET THE LENGTH OF RECTANGLE=3X

AND BREADTH=2X

ATQ

L xB =3456

3X x 2X =3456

6X^2 =3456

X^2=3456/6

X^2=576

X=√576

X=24

L=3(24)=72m

B=2(24)=48m

perimeter of rectangle=2(l+b)

=2(72+48)

=2(120)

=240m

cost of fencing 1m^2=60

for 3456m^2=3456 x 60

=21360 rs.

Answer 2

Step-by-step explanation:

$\huge\underline\blue{\sf</p><p>Answer}$

Let the length of the field be 3x m.

Then , it's breadth = 2x m.

So,area of field = ( 3x X 2x ) m²= (6x²)m²

_______________

But, area = 3456 m² (given)

So, 6x² = 3456 =} $\large{\sf {\frac{</strong><strong>3</strong><strong>4</strong><strong>5</strong><strong>6</strong><strong>}{</strong><strong>6</strong><strong>}}}$ = 576

$\large\implies{\sf </strong><strong>}$ x = √576 = 24.

Then, Length = ( 3 x 24) m = 72m and

Breadth = ( 2 x 24 ) m = 48 m.

:- PERIMETER OF FIELD = 2(l+b) units

$\large\implies{\sf </strong><strong>}$ 2( 72+48)m = (2 X 120) m = 240m.

________

So, the cost of fencing will be $\large\implies{\sf </strong><strong>}$ Rs ( 240 X 60) = Rs 14400