metallic sphere of radii 6cm ,8cm and 10 cm are melted to form a single solid sphere find radius of resulting sphere
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Answered by
9
volume of sphere1 = 4/3Π 6³
volume of sphere2 = 4/3Π 8³
volume of sphere3 = 4/3Π 10³
volume of new sphere = 4/3Π (6³+8³+10³)
= 4/3Π (1728)
= 4/3Π 12³
so radius = 12cm
volume of sphere2 = 4/3Π 8³
volume of sphere3 = 4/3Π 10³
volume of new sphere = 4/3Π (6³+8³+10³)
= 4/3Π (1728)
= 4/3Π 12³
so radius = 12cm
Answered by
5
The volume of the new sphere will be equal to the combined volume of the three smaller spheres.
Let the radius of new sphere be r cm, then
4/3 πr3 = 4/3 π(63 + 83 + 103)
⇨ r3 = 63 + 83 + 103
= 1728
r = 12 cm
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