Question

Methyl iodide on reduction with zinc and dilute HCL forms_______ *
Ethane
Isobutane
Methane
Propane​

Answer 1

Answer:

Alkyl halides (except fluorides) on reduction with zinc and dilute hydrochloric acid give alkanes.

CH3I loses iodine and takes up hydrogen, thus getting reduced to methane.

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Answer 2

C. Methyl iodide on reduction with zinc and dilute HCL forms Methane

• This is a reduction reaction in which alkyl halide in presence of Zinc and HCl and gets reduced to alkane.
• In this all alkyl halides except alkyl fluoride are reduced to its alkane form. As, we have seen in this example that Methyl Iodide is reduced to Methane.
• $CH_{3}I => CH_{4} + HI$ (zinc n dil. HCl).

Therefore, Methyl iodide on reduction with zinc and dilute HCL forms Methane.