Mg(s) Mg-- (1M) Cu++ (1M) (Cu)(s)
indicate cathode & anode
write reaction taking place at electrode
calculate the emf at 1M solution of ions
Answers
Answered by
6
Answer:
ANSWER
Given Zn∣Zn
2+
(0.001M)∣∣Cu
2+
(0.1M)∣Cu
Overall cell reaction:
Zn⟶Zn
2+
+2e
−
Cu
2+
+2e
−
⟶Cu
Zn+Cu
2+
⟶Zn
2+
+Cu
E
cell
o
=standard reduction potential of cathode + standard oxidation potential of anode
E
cell
o
=0.34 to 0.76 V
E
cell
o
=1.1 V
K
C
=
[Cu
2+
]
[Zn
2+
]
=
10
−1
10
−3
=10
−2
EMF of the cell at any electrode concentration is:
E=E
o
−
n
0.059
log(K
C
)=1.1−
2
0.059
log(10
−2
)=1.1−
2
0.059
×(2)=1.1−0.059=1.041V
Answered by
0
Answer:
It is connected through network. So, It is a chemistry.
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