Question

The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19,29 and

34 respectively is​

Answer 1

Step-by-step explanation:

5, 20, 25, 35, 40

∣

24,5,7,8

∣

22,5,7,4

∣

1,5,7,2

∴L.C.M.=5×2×2×5×7×2=1400

20−14=25−19=35−29

=40−34=6

∴ required number

=LCM−6

=1400−6

=1394.