Question

Mg2C3 ionises completely then vant hoff factor​

Answer 1

Answer:

Explanation:

Hg  

2

​  

Cl  

2

​  

⇌Hg  

2

2+

​  

+2Cl  

−

 

Here, n=3

Now,

α=  

n−1

i−1

​  

 

0.8=  

3−1

i−1

​  

 

i=2.6

Answer 2

Van't Hoff factor for Mg2C3 if there is complete ionization.

Explanation:

The compound Mg2C3 is called Magnesium allylenide or Magnesium carbide. It will ionize into:

$Mg_{2}C_{3} --> 2Mg^{+2} + C^{+4}_{3}$

The total number of ions after ionization will be 3.

So, the Van't Hoff factor will be 3

• Van't Hoff factor is the indication of effect of solute particle on the colligative properties of the solution.
• These colligative properties depend on the number of ions present in the system.
• For non electrolytes ( solutes that neither associate nor dissociate like urea), Van't Hoff factor is always unity.