Question

Mia was running towards the playground. She had an initial velocity of 6 m/s, West and after 2 seconds she slowed down to 3 m/s, West. What was her deceleration?

A. 1.5 m/s², West. C. 6 m/s², West
B.-1.5 m/s², West D.-6 m/s², West
please answer it​

Answer 1

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B) -1.5m/s^2

Explanation :-

Acceleration is defined as the rate of change of velocity of a body.

Acceleration of a body in opposite direction of its motion is called Retardation or Declaration.

Now we have been given that Mia was running towards the playground. She had an initial velocity of 6 m/s, West and after 2 seconds she slowed down to 3 m/s, West. What was her deceleration?

From above data we can conclude that :

• Initial velocity = 6m/s
• Final velocity = 3m/s
• Time taken to slow down = 2s
• Deceleration = ?

Now we know that, acceleration :-

$a = \frac{v - u}{t}$

After inputting the values we get :

$a = \frac{3 - 6}{2}$

$a = \frac{ - 3}{2}$

$a = - 1.5 \frac{m}{ {s}^{2} }$

Here (-) represents deceleration.

_______________________________________

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Answer 2

We have,

Initial velocity = 6 m/s (W)

Final velocity = 3 m/s (W)

Time taken = 2 s

We know,

a = ∆v/∆t

⇒a = (3 m/s - 6 m/s)/(2 s) W

⇒a = (- 3 m/s)/(2s), W

⇒a = - 1.5 m/s², West. {Answer}.

∴ (B.) is the correct answer.