Question

Michael Jordan has a vertical leap of 1.25 m. What is his takeoff speed and for how much time he will be in the air? Take a = 10 m/s downwards.​

Answer 1

Answer:

ANSWER

Given, acceleration a=−g=−9.8m/s

2

(minus sign for motion against gravity); final velocity (top most point) is v=0m/s

Vertical distance traveled d=1.29m

If u be the initial velocity, using formula v

2

−u

2

=2ad

0

2

−u

2

=2(−9.8)(1.29)

⟹ u=5.03m/s

If t be the time to peak.

Using v=u+at

0=5.03−(9.8)t

We get t=5.03/9.8=0.513s

So, the hang time will be double of peak time i.e. t

hang

=2×0.513=1.03s