Math, asked by salumenon, 11 months ago

michiko has a metal container in the shape of a cuboid.The container is 2.4m long,1.2m wide and 0.6m high.Michiko plans to paint all the outside faces of the container with two coats of metal paint.a)how many tins of paint does michiko need to buy?b) what is the total cost of paint?.cost of metal paint is $ 8.49 and size of tin is 250 ml snd paint coverage is 4.5 metre square per litre​

Answers

Answered by himanshu87933
4

Answer:

2.4*1.2*0.6

%5%83838853585888

Answered by eudora
11

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

Step-by-step explanation:

Surface area of cuboid = 2lw + 2lh + 2hw

Length (l) = 2.4 m

Width (w) = 1.2 m

Height (h) = 0.6 m

SF = 2(2.4 × 1.2) + 2(2.4 × 0.6) + 2(0.6 × 1.2)

    = 5.76 + 2.88 + 1.44

    = 10.08 meter²

Paint coverage is 4.5 meter² per liter.

Total paint used in one coat = \frac{10.08}{4.5}

                                               = 2.24 liters

Paint used in double coats = 2.24 × 2 = 4.48 liters

a) Size of one tin paint = 250 ml

1 liters = 1000 ml

4.48 liters = 4.48 × 1000 = 4480 ml

Number of tins needed by Michiko = \frac{4480}{250}

                                                           = 17.92 ≈ 18 tins

b) Cost of one tin of metal paint = $8.49

∴ cost of 18 tins of paint = $152.82

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

Learn more about surface area of the room : https://brainly.in/question/14697911

Similar questions