Mid point of (2,3) (x, 5) is 5 then find the value of x.
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(x1,y 1) =(2,3) and (x2,y2)=(X,5)
Applying mid point theorem:
x1+x2/2=2+X/2
> 2+X/2= 5
> 2+X= 10
> X= 10-2= 8
Hence , X = 8.
Praneeth331:
hi rehu
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Question
Mid point of (2,3) (x, 5) is 5 then find the value of x.
Answer:
(x1,y 1)
⇒(2,3) and (x2,y2)
⇒(X,5)
Applying mid point theorem:
⇒ x1+x2/2=2+X/2
⇒ 2+X/2= 5
⇒ 2+X= 10
⇒ X= 10-2= 8
Hence , X = 8.
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