middle term factorisation of
15x2-5x-120
Answers
Answer:
5 • (x - 3) • (3x + 8)
Step-by-step explanation
STEP
1
:
Equation at the end of step 1
((3•5x2) - 5x) - 120
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
15x2 - 5x - 120 = 5 • (3x2 - x - 24)
Trying to factor by splitting the middle term
3.2 Factoring 3x2 - x - 24
The first term is, 3x2 its coefficient is 3 .
The middle term is, -x its coefficient is -1 .
The last term, "the constant", is -24
Step-1 : Multiply the coefficient of the first term by the constant 3 • -24 = -72
Step-2 : Find two factors of -72 whose sum equals the coefficient of the middle term, which is -1 .
-72 + 1 = -71
-36 + 2 = -34
-24 + 3 = -21
-18 + 4 = -14
-12 + 6 = -6
-9 + 8 = -1 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 8
3x2 - 9x + 8x - 24
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (x-3)
Add up the last 2 terms, pulling out common factors :
8 • (x-3)
Step-5 : Add up the four terms of step 4 :
(3x+8) • (x-3)
Which is the desired factorization
Final result :
5 • (x - 3) • (3x + 8)