Math, asked by abhinavpandey7, 1 year ago

middle term split of x2-2.3rootx-9​

Answers

Answered by kartik2507
0

Step-by-step explanation:

 {x}^{2}  - 2 \sqrt{3}x - 9 \\   = {x}^{2}   +  \sqrt{3} x - 3 \sqrt{3} x - 9 \\  = x(x +  \sqrt{3} ) - 3 \sqrt{3} (x +  \sqrt{3} ) \\  = (x +  \sqrt{3} )(x - 3 \sqrt{3} ) \\  x +  \sqrt{3}  = 0 \:  \:  \:  \:  \:  \: x - 3 \sqrt{3}  = 0 \\ x =  -  \sqrt{3}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x = 3 \sqrt{3}  \\

hope you get your answer

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