middle term splitting method by 2or3 example
neerjabinu:
u mean quadratic factorisation technique?
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To factor :ax² + bx + c ,
1) Find the product of 1st and last term( a x c).
2)Find the factors in a way that
addition or subtraction of that factors is
3) Write the middle term using the sum of the
two new factors, including proper signs.
4) Group the terms to form pairs Factor each pair by finding common factors.
5) Factor out the shared terms.
1) Find the product of 1st and last term( a x c).
2)Find the factors in a way that
addition or subtraction of that factors is
3) Write the middle term using the sum of the
two new factors, including proper signs.
4) Group the terms to form pairs Factor each pair by finding common factors.
5) Factor out the shared terms.
Answered by
1
Example 1: x² + 5x + 6
x² + 5x + 6
=x² + 2x + 3x + 6
=x(x+2) + 3(x+2)
=(x+2)(x+3)
Example 2: x² - 5x + 6
x² - 5x - 6
=x² - 2x - 3x + 6
=x(x-2) -3(x-2)
=(x-2)(x-3)
Example 3: x² + x - 6
x² + x - 6
=x² + 3x - 2x - 6
=x(x+3) -2(x+3)
=(x+3)(x-2)
Example 4: x² - x - 6
x² - x - 6
=x² -3x + 2x - 6
=x(x-3) +2(x-3)
=(x-3)(x+2)
x² + 5x + 6
=x² + 2x + 3x + 6
=x(x+2) + 3(x+2)
=(x+2)(x+3)
Example 2: x² - 5x + 6
x² - 5x - 6
=x² - 2x - 3x + 6
=x(x-2) -3(x-2)
=(x-2)(x-3)
Example 3: x² + x - 6
x² + x - 6
=x² + 3x - 2x - 6
=x(x+3) -2(x+3)
=(x+3)(x-2)
Example 4: x² - x - 6
x² - x - 6
=x² -3x + 2x - 6
=x(x-3) +2(x-3)
=(x-3)(x+2)
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