Question

Mike bought 17 bottles of beer from a shop. He wants to
move these bottles to his car. If he can only carry 3 bottles at
a time, what is the minimum number of trips he needs to make
to carry these bottles?
Answer:
05
5.5
6
5.67​

Answer 1

The minimum number of trips he needs to make to carry these bottles is 6.

Given,

17 bottles of beer. He can only carry 3 bottles at a time.

To Find,

The minimum number of trips he needs to make to carry these bottles.

Solution,

To carry 3 bottles = 1 trip

To carry 1 bottle = 1/3 trip

To carry 17 bottles = (1/3)x17 = 5 + 2/3 trips

Here, we can see that Mike requires 5 trips to carry 15 bottles and 2 bottle remains. To carry these 2 bottles, Mike has to make one more trip.

So, to carry 17 bottles = 5 + 1 = 6 trips

Hence, the minimum number of trips he needs to make to carry these bottles is 6.

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Answer 2

Answer:

The minimum number of trips that Mike needs to make to carry these bottles of beer is $6$.

Explanation:

Given:

We have been given that Mike bought $17$ bottles of beer from a shop.

He can only carry $3$ bottles at a time.

To Find:

The minimum number of trips that Mike needs to make to carry these bottles of beer.

Solution:

He takes one trip to carry three bottles of beer.

Therefore, to carry one bottle he would take $\frac{1}{3}$ trip.

To carry $17$ bottles he would take $\frac{1}{3} \times 17 = 5 + 0.6$

Mike will take $5$ and one more trip to carry $17$ bottles of beer.  

$5 +1 = 6$

Final Answer:

Hence, the minimum number of trips that Mike will take to carry $17$ bottles of beer that he bought is $6$.

Link:

https://brainly.in/question/33661039?msp_srt_exp=4&referrer=searchResults

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