Question

mike ran ten laps around his school's 1/4 mile track in 15 minutes. He finishes his run at the exact same point that he started. What was his average velocity in miles per hour?

Answer 1

Answer:

His average velocity is 10 miles per hour.

Explanation:

Given : Mike ran ten laps around his school's 1/4 mile track in 15 minutes. He finishes his run at the exact same point that he started.

To find : What was his average velocity in miles per hour?

Solution :

Mike ran ten laps around his school's 1/4 mile track.

i.e. 1 lap = $\frac{1}{4}$ mile

10 lap =  $\frac{10}{4}=2.5$ mile

The distance covered is 2.5 mile.

Time taken to cover the track is 15 minutes.

Converting minutes into hour,

$1 \ min=\frac{1}{60}\ hr$

$15 \ min=\frac{15}{60}\ hr$

$15 \ min=0.25\ hr$

The average velocity is given by,

$\text{Average velocity}=\frac{\text{Distance}}{\text{Time}}$

$\text{Average velocity}=\frac{2.5}{0.25}$

$\text{Average velocity}=\frac{25\times 100}{25\times 10}$

$\text{Average velocity}=10$

Therefore, His average velocity is 10 miles per hour.

Answer 2

His average velocity is 10 miles per hour.

Explanation:

Given :

Mike ran ten laps around his school's 1/4 mile track in 15 minutes. He finishes his run at the exact same point that he started.

To find : What was his average velocity in miles per hour?

Solution :

Mike ran ten laps around his school's 1/4 mile track.

i.e. 1 lap = $\frac{1}{4}$ mile

10 lap =  $\frac{10}{4}=2.5$ mile

The distance covered is 2.5 mile.

Time taken to cover the track is 15 minutes.

Converting minutes into hour,

$1 \ min=\frac{1}{60}\ hr$

$15 \ min=\frac{15}{60}\ hr$

$15 \ min=0.25\ hr$

The average velocity is given by,

$\text{Average velocity}=\frac{\text{Distance}}{\text{Time}}$

$\text{Average velocity}=\frac{2.5}{0.25}$

$\text{Average velocity}=\frac{25\times 100}{25\times 10}$

$\text{Average velocity}=10$

Therefore, His average velocity is 10 miles per hour.✅