Question

Mina is one-fourths the age of his father. In 12 years, he will be two-fifths the age of his father. Determine their present ages. ​

Answer 1

Step-by-step explanation:

let the Age of Mina be x

And Fathers be y

given

$x = \frac{y}{4} \\ \\ 4x = y \\ \\ after \: 12 \: years \\ \\ x + 12 = \frac{2}{5} (y + 12) \\ \\ 5(x + 12) = 2(y + 12) \\ \\ 5x - 2y + 36 = 0 \\ \\ 5x - 2(4x) + 36 = 0 \\ \\ 3x = 36 \\ \\ x = 12 \\ \\ y = 48$

Age of Mina is 12

Her Father is 48

Hope it helps

Answer 2

let the Age of Mina be x

Let y be the age of father:-

$\begin{lgathered}x = \frac{y}{4} \\ 4x = y \\ \: 12 \: years\: later \\ x + 12 = \frac{2}{5} (y + 12) \\ 5(x + 12) = 2(y + 12) \\ 5x - 2y + 36 = 0 \\ 5x - 2(4x) + 36 = 0 \\ 3x = 36 \\ x = 12 \\ y = 48 \\\end{lgathered}$

Mina age is 12

48 is the answer:-