Question

Minimum number of atoms required for emissions of all possible photons from 6th excited state?
a) 6. b) 8. C) 10. D) 12

Answer 1

The maximum n umber of atoms required for emission of all possible photons from 6th excited staet is 8.

Explanation:

• For one hydrogen atom, number of spectral lines is given by
• N = (n2−n1) (n2 − n1 + 1) / 2
• Here, n1 = 2 and n2  = 7
• n2 will be 7 as it is the 6th excited state
• Therefore, N = (7 − 2)( 7 − 2 + 1 ) 2 = 5 × 6 / 2 = 15
• Therefore, 15 lines are possible for one hydrogen atom.
• Therefore, for 8 hydrogen atoms maximum number of lines are 8 × 15 = 120 lines.