Math, asked by rajavardhangadimudi, 1 year ago

Minimum value of 27^cosx 81^sinx

Answers

Answered by amlanchandrarout
1

Min value of cos x = -1

Min value of sin x = -1

So,min value of

27^cosx 81^sinx= 27^(-1) 81^(-1)

= (1/27) (1/81)

= 1/2187

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