Question

Minimum value of 2cos square teta + 3 sin square teta

Answer 1

2cos²Q+3sin²Q
2(1-sin²Q)+3sin²Q
2-2sin²Q+3sin²Q
2+ sin²Q
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Answer 2

♧♧HERE IS YOUR ANSWER♧♧

Now,

2 cos²θ + 3 sin²θ

= 2 (1 - sin²θ) + 3 sin²θ, since sin²θ + cos²θ = 1

= 2 - 2 sin²θ + 3 sin²θ

= 2 + sin²θ

Now, for the minimum value of the given expression, we have to take θ = 0, because at θ = 0, sin0 = 0.

So, the required minimum value = 2.

Let me added the maximum value of the given expression.

When, θ = π/2, sin(π/2) = 1.

Thus, maximum value = 2 + 1 = 3.

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