Question

minimum value of sinx +cosx
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Answer 1

Answer:

Let F(X) =sinX +cos X

To find the local max or local min value of any (2 time differentiable) function apply the following steps:

Find F'(X) (i.e. 1st derivative of F) and equate it to be 0 and find X for that equation.

Find F''(X) (i.e. 2nd derivative of F) and put the value of X in F''(X) which we get in step 1. If the value of F''(X) is negative then F(X) has local max at X and if the value of F''(X) is positive then F(X) has local min at X.

Answer 2

Minimum value of sin x+ cosx(+,-)root 1^2+1^2 I.e +root2 is maximum value and - root2 is minimum value



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