Minimum value of y = x² – 3x +5, XE[-4,1]
is
seth87:
help me plz
x = 1 has minimum value,.
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Answered by
1
hey mate I hope it is correct answer
but I am not sure
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kk
sorry
I can't solve it
so sorry
please
answer is -20
kk you know i study in class 11
and you think i read in class 8 and 9
wow same here I am always in class 11 (non-medical
gud
Answered by
5
Solution:-
Given Quadratic Polynomial Equation:-
x² – 3x +5
For y = -4.
=) P(x) = x² – 3x +5
=) P(-4) = (-4)² + 3(-4) + 5
=) P(-4) = 16 - 12 + 5
=) P(-4) = 9
For y = 1.
=) P(x) = x² – 3x +5
=) P(1) = 1² - 3 + 5
=) P(1) = 1 + 2
=) P(1) = 3.
Hence,
The Minimum value of y for y = x² – 3x +5 is 3.
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