minoo has cut out two semicircular pieces from a square sheet of size 10 cm . find the area ansd the perimeter of the figure obtained.
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Area = area of square-area of two semicircles
=100-22/7*5*5
21.42
Perimeter =two sides of square+ perimeter of circle
=10+10+2*22/7*5
=51.42
=100-22/7*5*5
21.42
Perimeter =two sides of square+ perimeter of circle
=10+10+2*22/7*5
=51.42
DPR05:
Of course area unit is cm^2 and perimeter is cm
Answered by
0
The area of the figure is 21.46 cm² and the perimeter is 51.42 cm
Given:
Minoo has cut out two semicircular pieces from a square sheet of size 10 cm.
To find:
Find the area and the perimeter of the figure obtained.
Solution:
Formula used:
Area of the figure = Area of the square - Area of 2 semicircles
Perimeter of figure = Perimeter of circle + 2 [Side of square]
The side of the square = 10 cm
Hence, Radius of circle = 10 cm/2 = 5 cm
Area of figure = [10]² - 2 [π (5)²]
= 100 - 78.54 = 21.46 cm²
∴ Area of the resultant figure = 21.46 cm²
Perimeter of figure = 2π(5) + 2 [10]
= 31.42 + 20 = 51.42 cm
Therefore,
The perimeter of the figure is 51.42 cm
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