Question

Mixture A is 10% ethanol by volume and mixture B is 30% ethanol by
volume. How many milliliters of mixture B must be added to 200 milliliters
of mixture A to create a mixture that is 25% ethanol by volume​

Answer 1

Given : Mixture A is 10% ethanol by volume and

mixture B is 30% ethanol by volume.

To Find :  How many milliliters of mixture B must be added to 200 milliliters

of mixture A to create a mixture that is 25% ethanol by volume​

Solution:

200 milliliters of mixture A

Mixture A is 10% ethanol by volume

=> ethanol = (10/100) 200  = 20  ml

Let say  100M  ml mixture B is mixed

mixture B is 30% ethanol by volume.

=> ethanol  = (30/100)100M  = 30M

Ethanol = 30M + 20  ml

Total Volume = 200 + 100M  ml

25% ethanol by volume​ = (25/100)(200 + 100M)

= 50 + 25M  ml

30M + 20 = 50 + 25M

=> 5M = 30

=> M = 6

=> 100M = 600

Hence 600 ml of mixture B  must be added

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