Math, asked by 111009111, 4 months ago

Mixture A is made with 5 cups of purple paint and 2 cups of white paint.

Mixture B is made with 15 cups of purple paint and 8 cups of white paint.



Which mixture is a lighter shade of purple?

Answers

Answered by jashsamani1101
0

Answer:

cup 2

Step-by-step explanation:

cup 2 = 15/23

cup 1 = 5/7= 15/21

both have same purple but cup 2 has more white so cup 2 is lighter

Answered by anjanakurup728
3

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Given:

Mixture A made up of 5 cups of purple paint and 2 cups of white paint

Mixture B is made with 15 cups of purple paint and 8 cups of white paint

To find:

Which mixture is lighter shade of purple = ?

Solution:

We know we have to find lighter shade of purple mixture so the white color paint should be more than purple color for lighter shade of purple color on comparison with two mixture A and B

In mixture A,

There are 2 cups of white paint

In mixture B

There are 8 cups of white paint

mixture B has lighter shade of purple color as it has less white color

Answer:

Therefore, Mixture B has lighter shade of purple color

Note:

On comparison, the mixture containing less purple color will have lighter shade

Another method:

In mixture A

2 cups of white paint contain 5 cups of purple paint

1 cup of white paint contain 5/2 = 2.5 cups of purple paint

In mixture B

8 cups of white paint contain 15 cups of purple paint

1 cup of white paint contain 15/8 = 1.875 purple paint

So, per cup(1 cup) of white paint contain more purple paint in mixture A while mixture B has low purple paint per white color on comparison with mixture A

So, mixture B has lighter shade of purple paint

HENCE PROVED

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