Question

MN parallel to BC and AM:MB=1:2 then area of triangle AMN /area of triangle ABC=

Answer 1

Answer:

answer is 1:9

Step-by-step explanation:

am=1

ac=3

Answer 2

The ratio of ar( ΔAMN ) to ar(ΔACB) is 1:9.

Step-by-step explanation:

Since we have given that

AM : MB = 1:2

So, AB = AM + MB = 1x+2x = 3x

Since MN is parallel to CB,

So, using the "Basic proportionality theorem", we get that

$\dfrac{ar(\Delta AMN)}{ar(\Delta ACB)}=\dfrac{AM^2}{AB^2}=\dfrac{1^2}{3^2}=\dfrac{1}{9}$

Hence, the ratio of ar( ΔAMN ) to ar(ΔACB) is 1:9.

# learn more:

n triangle ACB, MN parallel to side CB. MN divides triangle ACB into two parts equal in area, determine AM/MB

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