mo bisects qmn and no bisects mns if pq is parallel to rs.find mon
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90 degree will be the answer
sum of transversal interior angle of a same side is equal to 180 degree.
then we assume first interior angle is 100 then bisect 50 ,50
again the another angle is 80 degree then he was that 40 , 40
then in triangle Mon
40+50+X = 180
X = 180-90= 90°
sum of transversal interior angle of a same side is equal to 180 degree.
then we assume first interior angle is 100 then bisect 50 ,50
again the another angle is 80 degree then he was that 40 , 40
then in triangle Mon
40+50+X = 180
X = 180-90= 90°
jindalswayam132:
it is wrong method but answer is correct.
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