Question

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solution in attachment.
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Answer 1

-3/2a(2a-3b+4c)-5/6a(3a-2b-4)

first open the brackets

»(-3/2a×2a)-(3/2a×-3b)-(3/2a×4c)-(5/6a×3a)-(5/6a×-2b)-(5/6a×-4)

»-3a²+9/2b-6ac-5/2a²+5/3ab+10/3a

gruping the like terms

»(-3-5/2)a²+10/3a+9/2b+5/3ab-6ac

»-11/2a²+10/3a+9/2b+5/3ab-6ac

a=1 ; b=-2; c=-1

»(-11/2)+(10/3)-(9)-(10/3)+6

»-11/2-3

»-8.5