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A helicopter is flying at 3564m above ground. If an angle of 30° is subtened at a ground point by the helicopter position 100s apart, what is the speed of the helicopter?
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See this image. I have worked the problem.
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Answer:
Hope it helps you
Explanation:
20ms
−1
tan30=
3564
x
⇒V=
t
x
=
100
3564tan(30)
=20m/s
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