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D and E are respectively the points on the side a b and a c of a triangle ABC such that ad = 3 cm,BD=5 cm BC= 12.8 cm and DE || BC.The length of the DE is
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In Δ ABC, D and E are points on AB and AC , DE || BC and AD = 2.4 cm, AE = 3.2 cm, DE = 2 cm and BE = 5 cm. Hence,BD = 3.6 cm and CE = 4.8 cm. This discussion on D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 3 cm, BD = 5 cm, BC = 12.8 cm and DE || BC.
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Answer: DE = 4.8 cm
Explanation:
In ∆ADE & ∆ABC,
- ∠ADE = ∠ABC
- ∠AED = ∠ACB
(Alternate interior angles are same.)
Therefore, ∆ADE ~ ∆ABC (by AA criterion).
It implies that:
AD/AB = DE/BC
=> 3/8 = DE/12.8
=> DE = 3/8 × 12.8 = 4.8 cm
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