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A machine gun fires a bullet of mass 40 g with a velocity of 1200 m/s . The man holding it can exert a maximum force on 144 N on the gum . How many bullets can he fire per second at the most ??
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Answer:
3(three)
Explanation:
Given :m=40g=0.04kg.
v=1200m/s ,F=144N
Let n the no of bullets that can be fixed per second.
The force exerted by the man must balance the change in momentum of the bullets per second .
F=mnv or 144=0.04×v×1200 - n=3 bullets
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