Question

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$\sf ✰QUESTION✰$




$1. \: \sin62° - \cos \: 28° \:$
$2. \: cossec \: 35° - \sec \: 55°$
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Answer 1

Answer:

(1): 0

(2): 0

Step-by-step explanation:

A relation in sine and cosine is sin(90° - x) = cosx.

Similarly, cosec(90° - x) = secx.

(1): sin62° - cos28°

=> sin62° - sin(90° - 28°)

=> sin62° - sin62°

=> 0

(2) cosec35° - sec55°

=> cosec35° - cosec(90° - 55°)

=> cosec35° - cosec35°

=> 0

Answer 2

$\Large\fbox{\sf\blue{Answer :}}$

$\large \mathfrak{Q1.}$ $\sf{sin62° - cos28°}$

$\to \sf{ sin62° - sin(90° - 28°) }$

$\to \sf{ sin62° - sin62°}$

$\implies \bf \red{0}$

• Hence, the solution for the first equation will be 0.

$\Large \mathfrak{Q2.}$ $\sf{cosec35° - sec55°}$

$\to \sf{cosec35° - cosec(90° - 55°)}$

$\to \sf{cosec35° - cosec35° }$

$\implies \bf \red{0}$

• Hence, the solution for the second equation will also be 0.

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