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Given :-
a = -25
b = 20
c = 10
To Find :-
(i) a + (b + c) = (a + b) + c
(ii) a × (b + c) = a × b + a × c
Solution :-
(i) a + (b + c) = (a + b) + c
Taking LHS
a + (b + c)
-25 + [20 + (-10)]
-25 + [20 - 10]
-25 + 10
-15
Taking RHS
(a + b) + c
[(-25) + 20] + (-10)
[-25 + 20] - 10
-5 - 10
-15
Hence, Proved
(ii) a × (b + c) = a × b + a × c
Taking LHS
-25 × [20 + (-10)]
-25 × [20 - 10]
-25 × 10
-250
Taking RHS
[(-25) × 20] + [(-25) × (-10)]
-500 + (250)
-500 + 250
-250
Hence, Proved
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