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Answer 1

Explanation:

Let M be the minimum molecular weight of the compound.

7% of the compound is sodium. It is equal to

$\frac{7}{100} \times m = 0.07mg$

sodium in 1 mole of compound.

At least, 1 mole of Na will be present in 1 mole of compound.

1 mole of sodium weighs 23 g.

$m = \frac{23}{0.07} = 329g\mol$

Thus, 0.07M =23Thus, the minimum molecular weight of the compound is 329 g/mol.

Hence, the correct option is C

Answer 2

Answer:

Let M be the minimum molecular weight of the compound.

7% of the compound is sodium. It is equal to

\frac{7}{100} \times m = 0.07mg

100

7

×m=0.07mg

sodium in 1 mole of compound.

At least, 1 mole of Na will be present in 1 mole of compound.

1 mole of sodium weighs 23 g.

m = \frac{23}{0.07} = 329g\molm=

0.07

23

=329g\mol

Thus, 0.07M =23Thus, the minimum molecular weight of the compound is 329 g/mol.

Hence, the correct option is C