Question

mohan and ram are standing 5m apart facing the east direction, with mohan to the right of ram. they both walk straight for 7m. mohan takes a right turn to walk 5m, takes another right to walk 7m and stops. ram takes a left turn to walk 7m, takes a right turn to walk 5m and stops. what is the distance between them?
a. 24m
b.12√2m
c.20m
d.√433m​

Answer 1

Answer:

I hope this answer is helpful for you

Answer 2

Answer:

(d)The distance between ram.and mohan is

$\sqrt{433} \: m$

Step-by-step explanation:

This problem can be solved using co ordinate geometry.

Let the initial position of ram be A(0,5) Since from east perspective as mohan is on right of ram at a distance of 5m,his position is B(0,0)

=>As both walk straight for 7m,Their new positions become A'(7,5) and B'(7,0).

=>Mohan takes a right turn and walks 5m,his position is B"(7,-5) he takes another right turn and walks 7m.His position is B'''(0,-5).

=>Ram takes left turn to walk 7m,his position is A"(7,12) he takes a right turn to walk 5m,his final position is A"'(12,12).

The final positions of Ram and mohan are (12,12) and (0,-5) Hence the distance between them is given as

$d = \sqrt{(12- 0) {}^{2} + (12 - ( - 5)) {}^{2} } \\ = \sqrt{12 {}^{2} + 17{}^{2} } = \sqrt{433} \: m$

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