Math, asked by bhadsonsaini3890, 1 year ago

Mohan and sohan have an age ratio of 15: 8. after 10 years it will be 5:3. their present ages (in years) are

Answers

Answered by vmhetre201
3
Mohans Age 15x years
sohans age 8x years
by the conditions

15x+10/8x+10=5/3
3(15x+10) = 5(8x+10)
45x+30 = 40x + 50
45x+40x = 50-30
5x = 20
x = 20/5
x = 4
Mohans Age 15x = 15×4 = 60 years
sohans Age 8x = 8×4 = 32 years

Hope it helps !
Answered by Anonymous
3
heya mate

here your answer goes like this



let ,

their present ages to be

15x , 8x

after 10years their ages = 5x , 3x

ATP

15x + 10/8x+10 = 5/3

=> 3 (15x + 10) = 5 (8x+10)

=> 45x + 30 = 40x + 50

=> 45x - 40x = 50-30

=> 5x = 20

=> x = 20/5

=> x = 4

so mahan's present age = 15x = 15×4 = 60

sohan present age = 8x = 8×4 = 32


thanks! !!
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