Question

• Mohan sells an article to Ram at 10%
profit and Ram further sells it to Shyam
at 20% profit. If Shyam pays Rs.1320 to
Ram. Then find the cost price for Mohan.​

Answer 1

Step-by-step explanation:

c.p=(100/100+profit%)*s.p

=(100/100+20)*3120

=26007 years agoHelpfull: Yes(2) No(3)price for ram *(1.2) *(1.3)= 3120

price for ram=20007 years agoHelpfull: Yes(1) No(0)it is tha case of succesive percentage

20+30+20*30/100=56%

x+x*56/100=3120

x=2000 ans7 years agoHelpfull: Yes(1) No(0)2000,,,

X+30X/100 =3120

X=2400

Y+20Y/100 =2400

Y=2000.....7 years agoHelpfull: Yes(0) No(0)Answer:

Rs.2000.

Let cost price of table for ram=x.

Shyam's cost price=(x+20x/100)

sohn's cost=3120=((x+(20x/100))*(30/100)) + (x+(20x/100))

After solving,

==>x=2000

Answer 2

Answer:

The cost price for Mohan is Rs 1000.

Given:

• Mohan sells an article to Ram at 10% profit and Ram further sells it to Shyam at 20% profit. If Shyam pays Rs.1320 to Ram. Then find the cost price for Mohan.

To find:

• The cost price for the Mohan.

Solution:

For transition of Shyam and Ram,

Let be cost price for Shyam be x.

According to given:

Selling price for Shyam is Rs 1320,

Profit % = 20,

$\sf{C.P. = \dfrac{S.P.\times100}{100+Profit \%}}$

=> C.P. = (1320 × 100) / (100 + 20)

=> C.P. = 132000/120

=> C.P. = Rs 1100...(1)

_________________________

Now, for transition of Mohan and Shyam,

As article is sold to Shyam by Mohan

For Mohan S.P. of article = Rs 1100 ... from (1)

Profit % = 10...(given)

=> C.P. = (1100 × 100) / (100 + 10)

=> C.P. = 110000/110

=> C.P. = Rs 1000

Therefore, the cost price for Mohan is Rs 1000.