Mohan started a business with Rs.5000 in March. He lost Rs.1500 in March, gained Rs.1000 in April, gained Rs.2000 in May and lost Rs.500 in June. Find the money left with Mohan at the end of the month of June.
Answers
Step-by-step explanation:
the money left with Mohan at the end of the month of June is rupees 6000
Answer:
1. Find the simple interest, when:
(i) Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
(ii) Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
(iii) Principal = Rs 4500, Rate of Interest = 4% per annum and Time = 6 months.
(iv) Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months.
(v) Principal = Rs 1000, Rate of Interest = 10% per annum and Time = 73 days.
Solution:
(i) Given Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2000 × 5 × 5)/100
= Rs 500
(ii) Given Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (500 × 4 × 12.5)/100
= Rs 250
(iii) Given Principal = Rs 4500, Rate of Interest = 4% per annum and Time = 6 months = ½ years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (4500 × ½ × 12.5)/100
SI = (4500 × 1 × 12.5)/100 × 2
= Rs 90
(iv) Given Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months = (4/12) = (1/3) years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (12000 × (1/3) × 18)/100
SI = (12000 × 1 × 18)/100 × 3
= Rs 720
(v) Given Principal = Rs 1000, Rate of Interest = 10% per annum and
Time = 73 days = (73/365) days
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (1000 × (73/365) × 10)/100
SI = (1000 × 73 × 10)/100 × 365
= Rs 20