Question

Mohan Travels 28 kilometre due north and then 21 kilometre due east what is the least distance that he could have travelled from the starting point?​

Answer 1

Answer:

The least distance he could have travelled is 35km.

Step-by-step explanation:

We know that,

Starting point is -( A)

Mohan travels 28 km north.( name this point as B)

Then, 21 km east. (name this point as C)

Therefore, shortest distance is AC and this forms a right triangle hypotenuse.

Thus,

AC^2 = AB^2 + BC^2

Therefore, AC = root of (21^2 +28^2)

Thus, AC = 35km.

Therefore, the shortest distance he travelled  from starting point is 35 km .

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