Math, asked by chinnaswamyvenkatesh, 7 months ago

mohans mother is 20 years older than him .ten years ago ,she was thrice times as old as mohan was then.find their present ages if you answer with steps l will make u as brainliest.​

Answers

Answered by Anonymous
24

Answer :

Present age of Mohan is 20 years and present age of his mother is 40 years.

Given :

  • Mohan's mother is 20 years older than him.
  • 10 years ago, she was thrice as old as Mohan was then.

To find :

  • Their present ages.

Solution :

Consider,

  • Present age of Mohan = x years.

His mother is 20 years older than him.

Then,

  • Present age of his mother = (x+20) years.

10 years ago,

  • Age of Mohan = (x-10) years
  • Age of his mother = (x+20-10) = (x+10) years.

According to the question :-

  • 10 years ago, she was thrice as old as Mohan was then.

→ x+10 = 3(x-10)

→ x + 10 = 3x - 30

→ x - 3x = -30 -10

→ -2x = -40

→ 2x = 40

→ x = 40/2

→ x = 20

★ Present age of Mohan = 20 years

★ Present age of his mother = (20+20) = 40 years.

Answered by Anonymous
14

Let ,

The age of mohan be " x "

Given ,

The age of Mohan's mother is 20 years older than him

Thus ,

Age of Mohan's mother = x + 20

Ten years ago ,she was thrice times as old as mohan was then

Thus ,

x + 20 - 10 = 3(x - 10)

x + 10 = 3x - 30

-2x = -40

x = -40/-2

x = 20

 \therefore The present ages of mohan and her mother are 20 years and 40 years

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