Math, asked by Bhavishya50, 11 months ago

Mohit borrowed a certain sum at 5% per
annum compound interest and cleared this
loan by paying 12,600 at the end of the first
year and 17,640 at the end of the second
year. Find the sum borrowed.

jiseki gand me dam hai to solve karke dikhao​

Answers

Answered by woonnaamith
6

Answer:

Step-by-step explanation:

Amount with interest paid at the end of first year = Rs. 12600.

A = P (1+r/100)ⁿ

Principal at the starting of the first year = 12600 = P (1+5?100)¹

12600 = 105P/100

P = (12600 × 100)/105

P = Rs 12000. 

Amount with interest paid at the end of second year = Rs 17640.

Principal at the starting of second year = 17640 = P (1+5/100)¹

17640 = 105P/100

P = (17640 × 100)/105

P = Rs 16800

Total sum borrowed = 12000 + 16800 = Rs 28800


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Answered by eshanmanoj23oct
1

Answer:

hope it helps u

Step-by-step explanation:

Amount with interest paid at the end of first year = Rs. 12600.

A = P (1+r/100)ⁿ

Principal at the starting of the first year = 12600 = P (1+5?100)¹

12600 = 105P/100

P = (12600 × 100)/105

P = Rs 12000.  

Amount with interest paid at the end of second year = Rs 17640.

Principal at the starting of second year = 17640 = P (1+5/100)¹

17640 = 105P/100

P = (17640 × 100)/105

P = Rs 16800

Total sum borrowed = 12000 + 16800 = Rs 28800

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