Mohit invests 8,000 for 3 years at a certian rate of interest,
compounded annually. At the end of 1st year it amounts to 9,440.
Calculate.
(i) the rate of interest per annum.
(ii) the amount at the end of the second year.
(iii) the interest accrued in the third year.
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Answer:
I)rate of interest per annum=18%
II) Amount=10880
III) INTEREST=4320
Step-by-step explanation:
P=8000
R=x%
T=1yrs
Amount=P+SI
9440=8000+SI
SI=9440-8000
=1440
SI=P×R×T
---------
100
1440=8000×x×1
----------------
100
x=8000×1. 8000
---------------- =. ------------
100 × 1440. 144000
=18%
ii)
P=8000
R=18%
T=2yrs
SI= P×R×T
---------
100
SI=8000×18×2
-----------------
100
=2880
amount=P+SI
=8000+2880
=10880
III)
P=8000
R=18%
T=3YRS
SI= P*R*T
----------
100
=8000*18*3
----------------
100
= 4320
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