mohit makes 8 full rounds of a rectangle field with length 120m and breadth 75m john make 10 full rounds of a square field with each side 100m find who covers larger distance and by how much
Answers
GivEn:
- Length of Rectanglular field = 120 m
- Breadth of Rectanglular field = 75 m
- Sides of square field = 100 m
To find:
- Who covers larger distance and by how much?
SoluTion:
As per given Question,
Mohit makes 8 full rounds of a rectangle field.
As we know that,
★ Perimeter of Rectangle = 2(l + b)
Distance covered by Mohit in one round = Perimeter of rectangular field
2(120 + 75)
2(195)
390 m
Therefore, Mohit covers 390 m to complete 1 round.
So, Distance covered by Mohit to complete 8 round is,
8 × 390
3120 m
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Now, In case of John,
John make 10 full rounds of a square field.
As we know that,
★ Perimeter of Square = 4 × side
Distance covered by John in one round = Perimeter of square field
4 × 100
400 m
Therefore, John covers 400 m to complete 1 round.
So, Distance covered by John to complete 10 round is,
400 × 10
4000 m
Therefore, we can say that John covers greater distance than Mohit.
John covers greater distance than Mohit by,
4000 - 3120
480 m
★ Additional Information:
- Area of Rectangle = l × b
- Area of Square = side × side
Answer
Case - 1 : Mohit
Length of rectangle = 120 m
Breadth of rectangle = 75 m
No. of rounds = 8
So , Distance covered by Mohit is equals to 8 times the perimeter of rectangle
So , Distance moved by Mohit is 3120 m
_________________________
Case - 2 : John
Side of square = 100 m
No. of rounds = 10
So , Distance moved by john is equals to 10 times the perimeter of square
So , Distance moved by John is 4000 m
_________________________
So , John covers larger distance than Mohit by 880 m
[ ∵ 4000 - 3120 = 880 m ]