Biology, asked by rujal61891, 1 year ago

Moist heat sterilization of spores at 121 oC follows first order kinetics as per the expression: d dN k N dt  where, N is the number of viable spores, t is the time, kd is the rate constant and dN dt is the rate of change of viable spores. If kd value is 1.0 min-1 , the time (in minutes) required to reduce the number of viable spores from an initial value of 1010 to a final value of 1 is (up to two decimal places)

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Answered by sachin3732
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Moist heat sterilization of spores at 121 oC follows first order kinetics as per the expression: d dN k N dt  where, N is the number of viable spores, t is the time, kd is the rate constant and dN dt is the rate of change of viable spores. If kd value is 1.0 min-1 , the time (in minutes) required to reduce the number of viable spores from an initial value of 1010 to a final value of 1 is (up to two decimal places)

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