Question

Molality of aqueoussolution solution of is 3 the mass percentage of urea in the solution

Answer 1

Answer:

Mass percentage of urea = 15.25%

Explanation:

Total %age of solution = 100%

Let %age of solute (urea) = x%

Therefore %age of water=100-x%

Now moles of urea= x/molar masss

ie... x/60

Wgt of solvent= 100-x/1000

Therefore by eqn of molality

xtimes 1000/60 times (100-x)=3

Solving for x we get.... X=15.25

Therefore required mass %age of urea = 15.25%