Question

Molar conductances of BaCl₂, H₂SO₄ and HCl at infinite
dilutions are x₁, x₂ and x₃ respectively. Equivalent
conductance of BaSO₄ at infinite dilution will be :
(a) (x₁ + x₂ – x₃) /2 (b) x₁ + x₂ – 2x₃
(c) (x₁ – x₂ – x₃) /2 (d) (x₁ + x₂ – 2x₃) /2

Answer 1

The equivalent  conductance of BaSO₄ at infinite dilution will be

λ∞eq.= 1 / 2(x1 + x2 + x3)

Option (D) is correct.

Explanation:

We are given:

• The molar conductance of  BaCl₂ =  x1
• The molar conductance of H₂SO₄ = x2
• The molar conductance of HCl = x3

λ∞m(BaSO4) = λ∞Ba2+ + λ∞SO2−4

λ∞m (BaCl2) + λ∞m(H2SO4)^−2 λ∞m(HCl)

= x1 + x2 − 2x3  

and λ∞eq.= 1 / 2λ∞m(BaSO4)

λ∞eq.= 1 / 2(x1 + x2 + x3)

Thus the equivalent  conductance of BaSO₄ at infinite dilution will be

λ∞eq.= 1 / 2(x1 + x2 + x3)

Also learn more

Molar conductivity of a weak acid HA at infinite dilution is 345.8 S cm2/mol. Calculate molar conductivity of 0.05 M HA solution. Given that alpha = 5.8 ?? 10-6.

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