Question

In electrolysis of NaCl when Pt electrode is taken then H₂ is
liberated at cathode while with Hg cathode it forms sodium
amalgam. This is because
(a) Hg is more inert than Pt
(b) more voltage is required to reduce H⁺ at Hg than at Pt
(c) Na is dissolved in Hg while it does not dissolve in Pt
(d) conc. of H⁺ ions is larger when Pt electrode is taken

Answer 1

Explanation:

In electrolysis of NaCl when Pt electrode is taken H_(2) is liberated at cathode while Hg cathode it forms sodium amalgam because. When Pt electrode is used, H2O is reduced as its reduction potential is higher than that of Na+ ions.

Answer 2

Explanation:

In electrolysis of NaCl when Pt electrode is taken then H₂ is

liberated at cathode while with Hg cathode it forms sodium

amalgam. This is because

(a) Hg is more inert than Pt

(b) more voltage is required to reduce H⁺ at Hg than at Pt

(c) Na is dissolved in Hg while it does not dissolve in Pt✔️

(d) conc. of H⁺ ions is larger when Pt electrode is taken